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Q: What is the smallest number of the product of 2 different primes that are squared?

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The two smallest prime numbers are 2 and 3. So, the smallest number that is a product of two different primes that are squared is 22 x 32 = 36.

25 is the smallest two didgit squared number

The smallest prime factors are 2,3,5,7 thus the smallest number would be the product of these will be 210

30

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Logically, the smallest number with 4 different prime factors would have to be the product of the smallest four prime numbers. So the smallest natural number with four different prime factors is 210 (2*3*5*7).

If by "least number" you mean "smallest positive integer", then the answer is the product of the three smallest primes: 2x3x5 = 30

A squared number is the product of an integer times itself. So, 16 is a squared number. 4 * 4 = 16.

n = 5 245 * 5 = 1225 which is 35 squared

1155, 3x5x7x11=1155.

2×3×5×7=210

5*n2

6(X2)

As a product of its prime factors: 2*3*5*7 = 210

19

The smallest prime number greater than 50 is 53.

9 is the smallest natural number that is odd and composite: 9=3*3. 15 is the smallest natural number that is odd and a product of two numbers different from one and from each other: 15=3*5.

(y^2)x8

3 because 3x3=9

Their product.

102 is the smallest three digit number with different digits.

It'd be the product squared, since you're multiplying it by itself. the product of a number multiplied by itself is called an Exponent, Power or Square Number

If you allow 3 x 3 x 3 x 3, then 81. If they must be different then 1155.

The smallest prime number is 2 and the greatest prime number less than 100 is 97. The required product is: 2 x 97 = 194.

-98