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Q: What are the 10000 different number combinatons you can have using 0thru nine 4 digit combinations?

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extrapolate.... there are several different combinatons of compounds that are classified as plastics

Since a number can have infinitely many digits, there are infinitely many possible combinations.

4*3*2*1 = 24 different combinations.

If the 6 digits can be repeated, there are 1296 different combinations. If you cannot repeat digits in the combination there are 360 different combinations. * * * * * No. That is the number of PERMUTATIONS, not COMBINATIONS. If you have 6 different digits, you can make only 15 4-digit combinations from them.

Number of combinations = 45C6 = 45!/6!(45-6)! = 8,145,060

all numbers have to be different 720 360 (6*5*4*3*2*1), * * * * * Wrong. Combinations do not have to be different. Those are permutations. There are only 6C4 = 6*5/(2*1) = 15 combinations.

The number of 4 different book combinations you can choose from 6 books is;6C4 =6!/[4!(6-4)!] =15 combinations of 4 different books.

hot deserts

There is only one combination. The order of the digits in combinations makes no difference. They are considered as being different if they are permutations, not combinations.

-49

64

combinations

18 different combinations. When a coin is tossed twice there are four possible outcomes, (H,H), (H,T), (T,H) and (T,T) considering the order in which they appear (first or second). But if we are talking of combinations of the two individual events, then the order in which they come out is not considered. So for this case the number of combinations is three: (H,H), (H,T) and (T,T). For the case of tossing a die once there are six possible events. The number of different combinations when tossing a coin twice and a die once is: 3x6 = 18 different combinations.

there are 36 different combination possibilities. Try them all.

120 WRONG! That is the number of PERMUTATIONS. In the case of combinations, the order of the numbers does not matter, so there is only 1 5-number combination from 5 numbers.

There are 84 different combinations possible for the committee of 6, taken from4 students and 5 teachers.1.- The committee with 4 students has 4C4 number of combinations of 4 students out of 4 and 5C2 number of combinations of 2 teachers out of 5 to be combined with. The product of these two give the number of different combinations possible in a committee formed by 4 students and 2 teachers.2.- The committee with 3 students has 4C3 number of combinations of 3 students out of 4 and 5C3 number of combinations of 3 teachers out of 5 to be combined with. The product of these two give the number of different combinations possible in a committee formed by 3 students and 6 teachers.3.- The committee with 2 students has 4C2 number of combinations of 2 studentsout of 4 and 5C4 number of combinations of 4 teachers out of 5 to be combined with. The product of these two give the number of different combinations possible in a committee formed by 2 students and 4 teachers.4.- The committee with 1 student has 4C1 number of combinations of 1 student out of 4 students and 5C5 number of combinations of 5 teachers out of 5 to be combined with. The product of these two give the number of different combinations possible in a committee formed by 1 student and 5 teachers.We now add up all possible combinations:4C4âˆ™5C2 + 4C3âˆ™5C3 + 4C2âˆ™5C4 + 4C1âˆ™5C5 = 1(10) + 4(10) +6(5) + 4(1) = 84There are 84 different combinations possible for the committee of 6, taken from4 students and 5 teachers.[ nCr = n!/(r!(n-r)!) ][ n! = n(n-1)(n-2)âˆ™âˆ™âˆ™(3)(2)(1) ]

Given that 'ten different numbers' is all of them.. then including 0000, there will naturally be 10,000 combinations.* * * * *" ... there will naturally be 10,000" only if you don't know the difference between permutations and combinations.Orders do not affect combinations so that 1234 is the same as 4321, 1432, etc. The number of 4-digit combinationsis (10*9*8*7)/(4*3*2*1) = 210

Assuming that the six numbers are different, the answer is 15.

9

Two make combinations you would take 2x1=2 combinations only

if it is a four digit code then there are 5040 possible combinatons. If i were you i would set up a camera out of sight that could capture it or, use a thermal imaging camera to see which numbers are warm and which ones are not. That would only leave you with 24 combinations.

The whole point of combinations is that the order of the number (or items) does not matter. Once you specify what the second number is, you are no longer looking at combinations.

The number of combinations of six numbers that can be made from seven numbers will depend on if you can repeat numbers. In all there are over 2,000 different numbers that can be made.

There are 126 different 5 digit combinations. Note that the combination 12345 is the same as the combination 45312.

221,184 Different Combinations :)