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3*2 = 6

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Q: How many combination is there for 3 dishes and 2 bowls?
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In how many ways can you choose 2 side dishes out of 9?

There are 36 possible combinations.


How many combinations are there in 39 numbers?

It depends on how many numbers are in each combination. If there are 5 numbers in each combination, then you have 575,757 possibilities. If there are 2 in each combination, there you have 741 possibilities. If there's only 1 number in each combination, then there are only 39 possibilities.


How many two thirds cup cereal bowls can be filled from 10 cups of cornflakes?

10 cups is thirty "third-cups". so 30/2 ie 15 "two-third" cups.


How many ways can you choose 2 side dishes out of 9?

Assuming you want 2 different side dishes, they can be chosen in 9 × 8 ways, but as the order doesn't matter every combination has been chosen twice so that there are 9 × 8 ÷ 2 = 36 difference choices. There is a general formula for choosing r different items from a set of n items: nCr(n, r) = n!/(r!(n-r)!) where the exclamation mark means "factorial", which is n × (n-1) × (n-2) × ... × 2 × 1. eg 4! = 4 × 3 × 2 × 1 = 24. 0! is defined to be 1. For 2 items from 9 this gives: nCr(9, 2) = 9!/(2!(9-2)!) = 9!/(2!7!) = (9 × 8 × 7 × 6 × ... × 1)/((2 × 1) × (7 × 6 × ... × 1)) = (9 × 8)/2 = 36 (as before).


If you have 5 letters how many combinations can you make?

Suppose the 5 letters are A, B, C, D and E. The letter A can either be in the combination or not: 2 options for A. With each of these options, B can either be in the combination or not: 2 options for B - making 2*2 options so far. With each of the options so far, C can either be in the combination or not: 2 options for C - making 2*2*2 options so far. and so on. So for 5 letters there are 25 = 32 combinations. However, one of these is the combination that excludes each of the 5 letters - ie the null combination. Excluding the null combination gives the final answer of 31 combinations.

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