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If the numbers are all different, then 25C5 = 25*24*23*22*21/(5*4*3*2*1)

= 53,130.

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Q: How many combinations are there in set of 5 for numbers 1 25?
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If each number is different from all of the other numbers and the combinations are considered distinct unless they contain the same numbers in the same order, the answer is 25 X 24 X 23 X 22 X 21 = 6,375,600. If the combinations are distinct only if they do not contain the same numbers, irrespective of order, then the answer is (25 X 24 X 23 X 22 X 21)(5 x 4 x 3 x 2) = 53,130.


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