If the numbers are all different, then 25C5 = 25*24*23*22*21/(5*4*3*2*1)
= 53,130.
Assuming you meant how many combinations can be formed by picking 8 numbers from 56 numbers, we have:(56 * 55 * 54 * 53 * 52 * 51 * 50 * 49)/8! = (7 * 11 * 3 * 53 * 13 * 51 * 25 * 7) = 1420494075 combinations. (Also equal to 57274321104000/40320)
If each number is different from all of the other numbers and the combinations are considered distinct unless they contain the same numbers in the same order, the answer is 25 X 24 X 23 X 22 X 21 = 6,375,600. If the combinations are distinct only if they do not contain the same numbers, irrespective of order, then the answer is (25 X 24 X 23 X 22 X 21)(5 x 4 x 3 x 2) = 53,130.
If the order of the five in the set makes a difference, there are (25 x 24 x 23 x 22 x 21) = 6,375,600 sets.If the order doesn't matter, then there are (25 x 24 x 23 x 22 x 21) / (5 x 4 x 3 x 2 x 1) = 53,130 sets.
12 how come
9
There are 480,700 combinations and I am not going to even try to list them!
Their is 25 combinations
5*4*3*2*1 = 120 combinations. * * * * * No. The previous answerer has confused permutations and combinations. There are only 25 = 32 combinations including the null combinations. There is 1 combination of all 5 numbers There are 5 combinations of 4 numbers out of 5 There are 10 combinations of 3 numbers out of 5 There are 10 combinations of 2 numbers out of 5 There are 5 combinations of 1 numbers out of 5 There is 1 combination of no 5 numbers 32 in all, or 31 if you want to disallow the null combination.
There are 5245786 possible combinations and I am not stupid enough to try and list what they are!
Assuming you meant how many combinations can be formed by picking 8 numbers from 56 numbers, we have:(56 * 55 * 54 * 53 * 52 * 51 * 50 * 49)/8! = (7 * 11 * 3 * 53 * 13 * 51 * 25 * 7) = 1420494075 combinations. (Also equal to 57274321104000/40320)
If each number is different from all of the other numbers and the combinations are considered distinct unless they contain the same numbers in the same order, the answer is 25 X 24 X 23 X 22 X 21 = 6,375,600. If the combinations are distinct only if they do not contain the same numbers, irrespective of order, then the answer is (25 X 24 X 23 X 22 X 21)(5 x 4 x 3 x 2) = 53,130.
25
If you have to stick with positive whole numbers, then there are only two: 1 x 25 and 5 x 5
25 different combinations.
If the order of the five in the set makes a difference, there are (25 x 24 x 23 x 22 x 21) = 6,375,600 sets.If the order doesn't matter, then there are (25 x 24 x 23 x 22 x 21) / (5 x 4 x 3 x 2 x 1) = 53,130 sets.
It depends which operation you are carrying out. There are an infinite number of combinations.
25