To find how many counting numbers have four distinct nonzero digits that sum up to 11, we first identify all combinations of four distinct digits (from 1 to 9) that meet this criterion. The possible combinations of digits that add up to 11 are limited, and we can use combinatorial methods to list them. After identifying valid sets, we can calculate the permutations for each set (since the order of digits matters) to get the total count. Upon calculating, we find there are 24 valid combinations yielding 576 distinct numbers.
155
There are only five distinct odd digits.
Three - all nonzero digits are significant.
The number 12.300 has five significant digits. The nonzero digits (1, 2, and 3) are all significant, as well as the zero after the decimal point. Zeros between nonzero digits (like the zero after the decimal point) are also considered significant.
The 3-digit numbers are all the counting numbers from 100 to 999.That's (the first 999 counting numbers) minus (the first 99 of them).There are 900 of them.
1,2,3,4 1+2+3+4=10 4 times 3 times 2 times 1 =24 24 counting numbers
1235; 1253; 1325; 1352; 1523; 1532; 2135; 2153; 2315; 2351; 2513; 2531; 3125; 3152; 3215; 3251; 3512; 3521; 5123; 5132; 5213; 5231; 5312; 5321. These are 24 such numbers which have four distinct nonzero digits and add up to 11.
Not too sure of the question but how about 0.77775
No, counting numbers you can ignore or say they have an infinate number of significant digits. By counting numbers I mean things you count, or non measurements, or numbers you wouldn't round to significant digits anyway . Measurements always have significant digits.
155
Two - all nonzero numbers are significant.
There are only five distinct odd digits.
3 if there is a decimal present you start counting from the left with the first nonzero number and continue until there are no numbers left
Five. All nonzero digits are significant.
Three. All nonzero digits are significant.
Three - all nonzero digits are significant.
Three - all nonzero digits are significant.