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The maximum value represented in a 32-bit unsigned word is 232-1 = 4,294,967,295, so you can represent all numbers with 9 decimal places and some numbers with 10 decimal places in 32-bits. log(232-1) = 9.632959861 is the true answer.

Q: How many decimal places in a 32 bit word?

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(2 to the power of 16 ) - 1 = 65535

The word orbit has two syllables. (Or-bit)

1.91 X 1022=========Same decimal maneuver, but you lose those two exponent places! Think about it a bit.

Two or-bit

It can be any decimal number between 0 and 255.

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That depends on the computer architecture. Most modern architectures address memory down to the 8-bit byte, however some architectures (often supercomputers) only address to the memory word which may be 64 bits or more long. Early computer architectures had various sizes of addressable memory unit: individual bit, decimal digit, 10-digit signed decimal word, 12-digit/character decimal word, 5-bit character, 6-bit character, 12-bit word, 9-bit quarterword, 18-bit halfword, 36-bit word, 20-bit halfword, 40-bit word, 60-bit word, etc.

The word 'bit' has one syllable.

There are 25.4 millimetres in one inch. Therefore, rounded to two decimal places, 8 millimetres is equal to 8 / 25.4 = 0.31 inches.

That would be 216 - 1, or 65535.

(2 to the power of 16 ) - 1 = 65535

The word orbit has two syllables. (Or-bit)

You can represent 2^12 or 4096 numbers in 12 bits, if that's what you mean?

1.91 X 1022=========Same decimal maneuver, but you lose those two exponent places! Think about it a bit.

There are two syllables in the word tidbit. The syllables in the word are tid-bit.

1

Because six and a little bit somethings is more things than 3 and a little bit somethings.

16 bit(eg : 01F8) is one word.