Best Answer

for any polygon with 'n' number of sides, the number of diagonals will be

n(n-3) / 2

if n is 50, no. of diagonals will be 50(50-3)/2 = 47*25 = 1175

how do you get it?

take any polygon, say septagon i.e. with 7 sides

if you take 1 vertice, remainig vertices will be 7-1 that is 6.

there will be 2 consecutive vertices for any vertice, so here, this one has 2 consecutive vertices(its always like that) so the remaining vertices is 6-2 that is 4.

remember : a diagonal connects non consecutive vertices

so you know that from one vertice, there will be 4 diagonals.

multiply it by the total no. of vertices(here 7)

4*7 = 28

now divide this by 2

(since 2 vertices share the same diagonal)

therefore, 28/2 = 14 which is the no. of diagonals in a septagon.

so for an n-gon, the number of diagonals will be

n(n-3) / 2

hope it helps!

p.s. i figured it out myself during math class. then i tried it on many polygons.

🙏

🤨

😮

Study guides

☆

Q: How many diagonals in a 50-gon?

Write your answer...

Submit

Related questions

It has 1,345,890 diagonals

It has 9 diagonals

5 diagonals

170 diagonals.

24 diagonals

2 diagonals

It has 2 Diagonals!!!

There are 20 diagonals

20 diagonals

It has 27 diagonals

It has 2 diagonals

14 diagonals

In a heptagon there is 14 diagonals

A undecagon has 44 diagonals. A dodecagon has 54 diagonals. An octagon has 20 diagonals. A heptagon has 14 diagonals.

how many diagonals from a vertex a heptagon have

Improved Answer:-It has 14 diagonals

A rectangle has 2 diagonals

it has 44 diagonals :D

A pentagon has 5 diagonals.

A quadrilateral has 2 diagonals.

It ha 2 diagonals

A Nonagon has 36 diagonals

5 diagonals

There are five diagonals in a pentagon.

0 they have no diagonals