Best Answer

With 2 6-sided dices there are 6x6=36 combinations (6 for the first dice, 6 for the second dice)

Let put the question this other way: how many combinations with a total more than 8, namely 9, 10, 11 or 12 ?

9: 4 combinations: 4-5 or 5-4 or 6-3 or 3-6

10: 3 combination: 5-5 or 6-4 or 4-6

11: 2 combinations: 6-5 or 5-6

12: 1 combination: 6-6

So there are 10 combinations for "more than 9" thus there are 36-10=26 combinations for "less or equal to 8".

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Q: How many dice combinations total less than 8 2 6sided dice?

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There are 36 combinations of two dice. each have 1 to 6To get 10 or more requires 4 +6, 5 +5, 5 +6 , 6+5, 6 +4, or 6+6, which are 6 combinations, leaving 36-6 = 30 combinations of less than 1030/36 = 5/6 probability of getting sum less than 10

The answer depends on how many dice are in the SET of dice.

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The probability is 1, if the dice are rolled often enough.

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Assuming you're using 6-sided dice, The probability of rolling less than 4 on one die is 1/2. To roll 3 dice and get less than 4 on 2 (and only 2) of them is 3/8.

5/36

Assuming these are regular dice, the probability is 1.

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