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Q: How many different 2 digit numbers can be formed from the digits 2 6 7 and 8?

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Related questions

5040 different 4 digit numbers can be formed with the digits 123456789. This is assuming that no digits are repeated with each combination.

10,000

36

100000 - including numbers with leading 0s

Assuming they are non-zero and different, the answer is 6.

24 different numbers.

27 three digit numbers from the digits 3, 5, 7 including repetitions.

There are 3024 of them.

180 of them.

840

There are 60480 numbers.

24

500

5 x 10 x 5 = 250 different numbers, assuming there is no limit to each digits' use.

192, including ones containing repeat digits.

There are 5*4*3 = 60 such numbers.

The number of six digit numbers that you can make from ten different digits ifrepetitions of same digit on the six digit number is allowed is 1 000 000 numbers(including number 000 000).If no repetitions of the the same digit are allowed then you have:10P6 = 10!/(10-6)! = 151 200 different six digit numbers(six digit permutations form 10 different digits).

6 if you don't repeat any.

1 set

It is 120 if the digits cannot be repeated.

60 different numbers can be formed from the digits {1, 2, 3, 4, 5} is no repeats are allowed Any of the first digits can be chosen for the first digit, leaving 4 for the next and 3 for the final digit. Thus there are 5 × 4 × 3 = 60 different possible such permutations of 3 digits from the 5.

There are 5! = 120 such numbers.

The number 1234567890 can create about 39 of 40 4 digit numbers.

There are 320 such numbers.

There are 34 = 81 numbers.