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How many different 4 digit combinations are there for numbers 1 2 3 4 5 and last numbers are 4 5 no restrictions numbers can be repeated?
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∙ 11y ago
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∙ 11y ago
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How many number combinations are possible with three numbers?
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
How many combinations of 2 numbers are there in 6 numbers?
If numbers may be repeated . . . 36 If numbers may not be repeated . . . 30 If the sequence doesn't matter . . . 15
What are the possible combinations of a 3 digit lock for numbers 0 through 39?
Assuming that repeated numbers are allowed, the number of possible combinations is given by 40 * 40 * 40 = 64000.If repeated numbers are not allowed, the number of possible combinations is given by 40 * 39 * 38 = 59280.
If using the numbers 1 through 9 how many different 3 digit combinations can be made?
If you allow digits to be repeated (for example, 222 or 992), then there are 9 x 9 x 9 = 729 combinations. If you do not allow digits to be repeated, then there are 9 x 8 x 7 = 504 combinations.
How many different 4 digit combinations are there for numbers 12 3 4 5 and last numbers are 4 5 no restrictions they can repeat?
This question does not make sense since a combination is independent of the order of its elements. That is, the combinations 1245 and 5142 are the same. Consequently, there can be no "last " numbers in a combination.
How many number combinations are possible with three numbers?
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
How many combinations of 2 numbers are there in 6 numbers?
If numbers may be repeated . . . 36 If numbers may not be repeated . . . 30 If the sequence doesn't matter . . . 15
What are the possible combinations of a 3 digit lock for numbers 0 through 39?
Assuming that repeated numbers are allowed, the number of possible combinations is given by 40 * 40 * 40 = 64000.If repeated numbers are not allowed, the number of possible combinations is given by 40 * 39 * 38 = 59280.
How many different 4 digit combinations are there for numbers 1 2 3 (assuming all three numbers are used and no numbers can be repeated more than once) (For example, 1233 is acceptable, but 1133 is not.)?
NOT AN ANSWER:More acceptable combinations:1231 3213 2321More unacceptable combinations:1112 2222 3113Thanks.
If using the numbers 1 through 9 how many different 3 digit combinations can be made?
If you allow digits to be repeated (for example, 222 or 992), then there are 9 x 9 x 9 = 729 combinations. If you do not allow digits to be repeated, then there are 9 x 8 x 7 = 504 combinations.
What are the Possible combinations of numbers 0 through 9 if any numbers can be repeated in the combination?
How many numbers per combination?
How many different 4 digit combinations are there for numbers 12 3 4 5 and last numbers are 4 5 no restrictions they can repeat?
This question does not make sense since a combination is independent of the order of its elements. That is, the combinations 1245 and 5142 are the same. Consequently, there can be no "last " numbers in a combination.
I have an alarm system keypad numbered 1-4. How many potential 4 digit combinations are there if the numbers can be repeated?
If you have 4 positions, each of which can hold any of the ten digits, you have 10 to the power 4 combinations. If you can have only 4 different digits, you have 4 to the power 4 different combinations.
How many number combinations are there in 0-9999?
9999
What are the possible combinations of the digits 0 through 9 if number may be repeated in the sequence?
Infinite. If numbers can be repeated, the list could go on nonstop.
If using numbers 1 through 9 how many different 4 digit combinations can be made with no restrictions on order or repeats?
Each digit can appear in each of the 4 positions. There are 9 digits, therefore there are 9⁴ = 6561 such combinations.
If using numbers 0 through 9 how many different 2 digit combinations can be made?
If there are no restrictions on duplicated numbers or other patterns of numbers then there are 10 ways of selecting the first digit and also 10 ways of selecting the second digit. The number of combinations is therefore 10 x 10 = 100.
