An infinity:
1,01+ 1,99+ 8+ 8
1,02+ 1,98+ 8+ 8
or
(-1)+ 1+ 9+ 10
And you can add more decimal spaces and/or negative numbers.
I believe the question was badly asked (I think you meant WHOLE numbers [0,1,2] with non-negative integers).
There are many different combinations of six numbers, but the sum of those numbers would have to be 24.
7
There are many combinations of 2 numbers that sum to 70. Any combination of numbers where the first number is x and the second number is 70-x will sum to 70. For example: 69 and 1 68 and 2 67 and 3 66 and 4...
There are 165 of them and I do not have the patience to list them all.
8
There are many different combinations of six numbers, but the sum of those numbers would have to be 24.
There are 12 different combinations of 3 positive odd numbers that add up to 21. Namely: (There are many permutations of these combinations.) 1,1,9 1,3,17 1,5,15 1,7,13 1,9,11 3,3,15 3,5,13 3,7,11 3,9,9 5,5,11 5,7,9 7,7,7
7
3*5=15 5*3=15 15*1=15
There are many combinations of 2 numbers that sum to 70. Any combination of numbers where the first number is x and the second number is 70-x will sum to 70. For example: 69 and 1 68 and 2 67 and 3 66 and 4...
There are 165 of them and I do not have the patience to list them all.
8
If you have 12 possible numbers with multiple combinations then you should start out with making all the possible combinations; you will find theyre 20. Theyre four numbers out of the twleve that can be divisible by three; 3, 6, 9, and 12. There are 7 combinations where the combinations can equal those four numbers. So the odds of getting a sum divisible by three is 7/20.
There are two ambiguities in this question. First, the numbers 0 through 9 could mean integers or real numbers. If you meant real numbers the answer is infinite, so I presume you mean integers. More to the point, it depends on whether you are only counting combinations of 4 different numbers or allowing duplications (like 4, 4, 5, 5).
110
19
Are you asking which two positive integers when added together equal 5285? If so, which of the 2642 different combinations would you prefer? How about 1 & 5284.