9
Only 9 numbers can be used in the hundreds place, and all the 10 numbers can be used for the tens and units place.
So we have 9 x 10 x 10 = 900 three-digit numbers.
If the 6 digits can be repeated, there are 1296 different combinations. If you cannot repeat digits in the combination there are 360 different combinations. * * * * * No. That is the number of PERMUTATIONS, not COMBINATIONS. If you have 6 different digits, you can make only 15 4-digit combinations from them.
6
6 different combinations can be made with 3 items
32C3 = 4960
Six combinations: 123, 132, 213, 231, 312, 321
i guess the answer is 54. A group of three digits can be selected from the 5 digits in 9 ways and each group can be arranged in 3! (i.e., 6) ways respectively and hence the answer is 6*9=54
Only 1. In a combination, the order of the digits does not matter.
100! / 97! = 100 * 99 * 98 = 970200
There are 720 combinations if you use each of the digits only once per combination.
45
Using the word "combinations" in the English sense (as opposed to mathematical sense the expert has used) where it often used in the mathematical sense of the word "permutations": Assuming the hundreds digit must be at least 1 (eg 99 = 099 is not considered a three digit number), then: 9 x 10 x 10 = 900.
10,000.