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4!/(2!*2!) = 4*3*2*1/(2*1*2*1) = 6



4!/(2!*2!) = 4*3*2*1/(2*1*2*1) = 6



4!/(2!*2!) = 4*3*2*1/(2*1*2*1) = 6



4!/(2!*2!) = 4*3*2*1/(2*1*2*1) = 6
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11y ago

4!/(2!2!) = 4321/(212*1) = 6

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Q: How many different four figure numbers can be made using the digits 1 9 9 1?
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