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How many digits are used for printing the page numbers of abook that has 215 pages?
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∙ 10y ago
If all pages are numbered (usually page 1 is not numbered) then 537.
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∙ 10y ago
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How many digits are used for printing a page numbers of a book that has 163 pages?
381 digits.
When numbering the pages of a book 624 digits were used find the number of pages in the book?
This problem can be solved by applying the counting principle to digits in consecutive page numbers. To begin, we need to separate numbers into their numbers of digits in order to multiply the page numbers to find the number of digits needed to express them. Assuming that your book begins on page 1, there are 9 page numbers having one digit only (counting principle: 9 - 1 + 1 = 9). Since each of these pages is numbered with one digit, the number of digits used is 9 so far. Continue with the pages each numbered with two digits. These are pages 10-99, comprising 90 pages (99 - 10 + 1 = 90). Every page number multiplied by 2 digits each is 180. With the 9 digits coming from single-digit pages, the number of digits used so far is now 189. We can continue in the same manner for pages expressed with three digits, 100-999, but having 435 (624 total - 189 so far = 435) digits left, we probably won't be able to get through all the three-digit numbers. Also, a book is likely to have under a thousand pages. To find out how many pages are left, we divide the number of digits left by the number of digits needed for each page: 435/3 = 145 pages left. Since 145 pages only account for the pages numbered with three digits each, we need to add pages numbered with one and two digits each in order to find the total number of pages. Before 145 pages began to be accounted for, we had accounted for the digits of 99 pages (each numbered using one or two digits each), so the total number of pages is 99 + 145 = 244.
How many digits are used for printing the page numbers of a book with 100 pages?
This depends on exactly what you mean by "100 pages" If you mean exactly 100 enumerated page sides, then you can say: The first nine pages would have 1 digit, so that's 9. the next 90 pages would have two digits, so that's 180. The last page would have three digits. Add them all together and we get: 9 + 180 + 3 = 192 If on the other hand mean 100 pieces of paper (200 page sides), then we have: The first nine pages would have 1 digit, so that's 9. the next 90 pages would have two digits, so that's 180. The next 101 pages would have 3 digits, so that's 303. Adding those we get: 9 + 180 + 303 = 492
How many pages does the book have with 600 digits?
299 pages.
If it takes 1140 digits to number the pages of a book how many pages does it have?
1140
How many digits are are used for printing the page numbers of a book that has 115 pages?
Three digits.
How many digits are used for printing a page numbers of a book that has 163 pages?
381 digits.
How many digits are used for printing the page numbers of a book that has 163 pages?
There are 64 pages (100 - 163) that need 3 digits per page; 64 x 3 = 192. There are 100 pages (10 - 99) that need 2 digits per page; 100 x 2 = 200.There are 9 pages (1 - 9 ) that need one digit per page; = 9.So 9 + 200 + 192 = 401 digits.[Assuming that the last page, an even-numbered page, has no number.]
When 151 digits are used to number a book how many pages are there?
First 9 pages = 9 digit. That leaves 142 digits. @ 2 digit per page, that is 142/2 = 71 pages with 2-digit numbers. So, 9 pages with 1-digit numbers + 71 pages with 2-digit numbers = 80 pages.
When numbering the pages of a book 624 digits were used find the number of pages in the book?
This problem can be solved by applying the counting principle to digits in consecutive page numbers. To begin, we need to separate numbers into their numbers of digits in order to multiply the page numbers to find the number of digits needed to express them. Assuming that your book begins on page 1, there are 9 page numbers having one digit only (counting principle: 9 - 1 + 1 = 9). Since each of these pages is numbered with one digit, the number of digits used is 9 so far. Continue with the pages each numbered with two digits. These are pages 10-99, comprising 90 pages (99 - 10 + 1 = 90). Every page number multiplied by 2 digits each is 180. With the 9 digits coming from single-digit pages, the number of digits used so far is now 189. We can continue in the same manner for pages expressed with three digits, 100-999, but having 435 (624 total - 189 so far = 435) digits left, we probably won't be able to get through all the three-digit numbers. Also, a book is likely to have under a thousand pages. To find out how many pages are left, we divide the number of digits left by the number of digits needed for each page: 435/3 = 145 pages left. Since 145 pages only account for the pages numbered with three digits each, we need to add pages numbered with one and two digits each in order to find the total number of pages. Before 145 pages began to be accounted for, we had accounted for the digits of 99 pages (each numbered using one or two digits each), so the total number of pages is 99 + 145 = 244.
A book uses exactly 264 digits for its page numbers Each page is numbered and the first page is 1 which is obviously 1 digit How many pages does the book have?
Pages 1 - 9 each have one digit, and so in total they use 9. Pages 10 - 99 each have two digits. There are 90 pages there, so we have now used 9 + (90 x 2) = 189 digits. Our book uses 264 - 189 = 75 digits more than this. That equates to 25 pages with three digits: pages 100 to 124 inclusive. So the book has 124 pages. Pages 1 - 9: 9 digits Pages 10 - 99: 180 digits. Pages 100 - 124: 75 digits. Total: 264 digits.
The pages of a book are numbered and it's found that 495 digits are used How many pages were there?
There are 9 pages that use a single digit (pages 1-9), leaving 495 digits - 9 pages × 1 digit/page = 486 digits There are 90 pages that use 2 digits (pages 10-99), leaving 486 digits - 90 pages × 2 digits/page = 306 digits There are 900 pages that use 3 digits (pages 100-999); this would be 2,700 digits, so the number of pages is somewhere in the hundreds. 306 digits ÷ 3 digits/page = 102 pages in the hundreds. → total number of pages = 102 + 90 + 9 = 201 pages.
How many digits are used for printing the page numbers of a book with 100 pages?
This depends on exactly what you mean by "100 pages" If you mean exactly 100 enumerated page sides, then you can say: The first nine pages would have 1 digit, so that's 9. the next 90 pages would have two digits, so that's 180. The last page would have three digits. Add them all together and we get: 9 + 180 + 3 = 192 If on the other hand mean 100 pieces of paper (200 page sides), then we have: The first nine pages would have 1 digit, so that's 9. the next 90 pages would have two digits, so that's 180. The next 101 pages would have 3 digits, so that's 303. Adding those we get: 9 + 180 + 303 = 492
The pages in a book are numbered starting with 1 the book has 250 pages how many digits did the printer use in numbering the pages?
9 digits used for pages 1 to 9 (9 pages * 1 digit)180 digits used for pages 10 to 99 (90 pages * 2 digits)453 digits used for pages 100 to 250 (151 pages * 3 digits)Total = 9 + 180 + 453 = 642 digits used.(Of course a trick answer is 10 as there are only 10 possible different digits in decimal).
852 digits used to number the pages of a book how many numbered pages does the book have?
There are exactly 320 pages in 852 digits.
What are the first 5 billion digits of pi?
1 million numbers takes 512 pages and even that's too big for this website... you would need 976743 pages to get the first five billion numbers of pi.
How many digits are in 30 pages that begin with one and there is one whole number in each page?
There are 9 pages with a single digit (pages 1-9) = 9 digits There are 30 - 9 = 21 pages with two digits = 21 × 2 = 42 digits → There are 9 + 41 = 51 digits in total.
