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The cube has 8 vertices.

The number of ways to construct a triangle is (8 x 7 x 6) = 336 .

But there are 6 ways to wind up with the same triangle.

So the number of distinct ones is ( 8! )/( 5! x 3! ) = 56 .

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11y ago
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Q: How many distinct triangles can be constructed by choosing three vertices from among the corners of a unit cube?
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