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Q: How many liters of 9 percent salt solution and 18 percent salt solution are needed to make 18 liters of 10 percent salt solution?

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4.84

50 liters

256 liters

50 Liters of the 60% solution.

(x L)((12%) = (100 L)(2%)x = 16.7 liters

3.0 kg

80 liters

Let's say the total solution is 100 liters. 50 of the liters is glucose and 50 is water. We want to make the 50 glucose equal to 10% of the total solution. For that to happen, we need to make the total solution 500 liters (50 of the 500 would be a 10% solution). So we add 400 liters of water to the original 100 liter (50/50) solution. Take the total number of units and multiply by 4. Add that much in water.

10 percent acetic acid indicates there is .1 liters of acetic acid, which is equal to 1.75 moles, or 105 grams per liter. To make this solution, add 7 liters of the 2M solution to 1 liter of water, or 7/8 solution to 1/8 water.

144liters

Depending on the desired concentration of the solution !

50liters

Add 0,8 L of water.

69

50

I suppose that this solution doesn't exist.

3

6 litres of 50% + 4 litres of 25%

7 liters of a 20% acid solution consists of 1.4 liters of acid (20% of the total volume) mixed with 5.6 liters of water (80% of the total volume). The amount of acid isn't going to change in the new solution. You are just going to add enough water to make it a 10% solution instead of a 20% solution. So it will be more dilute. That means that 1.4 liters of acid will represent 1/10 of the volume of the new solution. So the total volume of the new solution will be 10 x 1.4 or 14 liters. The amount of water in the new solution will be 14 - 1.4 = 12.6 liters. That is a difference of 12.6 - 5.6 = 7 liters from the amount of water you started with. So you need to add 7 liters of water to the original 20% solution to make it a 10% solution. This makes sense because if you double the amount of the mixture from 7 liters to 14 liters and the amount of acid is unchanged, the solution will be half as strong.

A five percent solution of starch is quite simple to create. A solution of 20 parts water and one part of pure starch is all that is needed.

0.125 Molar solution! Molarity = moles of solute/Liters of solution Algebraically manipulated, Moles of copper sulfate = 2.50 Liters * 0.125 M = 0.313 moles copper sulfate needed ===========================

6 moles

newtest3

8 moles of KCl are needed.

Use liters to match other units. So. 100 ml = 0.1 liters Molarity = moles of solute/ volume ( liters in this case ) of solution 1 M NaCl = moles NaCl/0.1 liters = 0.1 moles NaCl (58.44 grams/1 mole NaCl) = 5.844 grams of NaCl needed to make solution.