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Q: Factorise 14x squared minus 39x minus 35?

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8x2-39x+45 = (8x-15)(x-3) when factored

3x2-39x-90 = (3x+6)(x-15) when factored

39x-6

This is 41x

39x2y326xy4The gcf is 13xy3 .

41x

(2x - 7)(7x + 5)

2x - 3= 9 x=

For x-2x= 3x-43x+1 x-2x= -x and 3x-43x+1 = -40x+1 so -x= -40x+1 subtract -x from both sides 0= -39x +1 -1 = -39x so 1=39x so x=1/39

2 - 39x - 50 = 4 + x -39x - 48 = 4 + x Add 39 x to both sides: -48 = 4 + 40x Subtract 4 from both sides: -52 = 40x Divide both sides by 40: x = -1.3

(7x - 5)(5x - 2)

(4x - 3)(5x - 6)

(7x + 5)(2x - 7)

-38y - 39x (Is that what you were asking for?)

They are three disjoint expressions.

It is a quadratic expression and when factored it is: (7x+5)(2x-7)

The Greatest Common Factor (GCF) is 13.

It is (7x+5)(2x-7) when factored

f(x)=.39x

If that's -39x, it factors to 3(x - 3)(4x - 1)

39x - 45 = 15x - 24

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In math, anything can equal 39. for example, x+40=39 if x= -1 and 13x=39 if x=3. Even the derivative of 39x is equal to 39.

you multiply 4 and 7 and keep the x so it would be 28x and then add 11 and you get 39x

(7x + 5)(2x - 7)(2x-7)(7x+5)