Assuming the question refers to the digits 1, 2, ... , 9 the answer is 1344 numbers.
Order does matter in this case so you need to use the formula for a Permutation with repetition allowed. This would be n^r where n=6 different numbers and r=6 possible places for each number to go when forming the full 6-digit number. 6^6 = 46,656 possible digits
There are 2000 such numbers.
There are 2000 such numbers.
Just six numbers... 345, 354, 435, 453, 534 & 543
There are 5 choices for every digit.Each of the first two can be any one of (1, 3, 5, 7, or 9).Each of the last five can be any one of (2, 4, 6, 8, or 0).The total number of possibilities is (5 x 5 x 5 x 5 x 5 x 5 x 5) = 57 = 78,125This is only 0.78125% of the 10 million possible numbers if all 10 digits were allowed in any position.
None. Nine digit number cannot be formed using only five digits 1,2,3,4,5 in the case none of the digits can repeat. -------- Egad! I misread the question, apologies to the questioner. And thanks to Miroslav.
If repeated digits are allowed, then the largest 12-digit number is 999,999,999,999 .If repeated digits are not allowed, then the largest 12-digit number is 989,898,989,898 .If the same digit can't be used more than once, then the largest possible number has only10 digits. The number is 9,876,543,210 .
03458
Assuming all 45 digits are different (which they will not be if they are ordinary integers), then 456, if repetitions are allowed. That is 8303765625. If repetitions are not allowed then the number falls to 45*44*43*42*41*40 = 5864443200
36
The number is 36.
The least number of significant figures in any number of the problem determines the number of significant figures in the answer.