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Q: How many four digit numbers can be formed from digits 1 2 3 4 if repeated is allowed and how many are odd numbers?

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24

500

There are 5*4*3 = 60 such numbers.

5040 different 4 digit numbers can be formed with the digits 123456789. This is assuming that no digits are repeated with each combination.

If the digits may not be repeated, there are 6x5x4x3x2x1 = 720 numbers, If digits can be repeated, the answer is 6x6x6x6x6x6 = 46,656 numbers If zero is ong the available digits but is excluded from the first place. 5x6x6x6x6x6=38,880 numbers

1 set

It is 120 if the digits cannot be repeated.

27 if the digits can be repeated. 6 if not.

3x3x3=27

36

6*6*3 = 108 numbers.

This permutation problem depends on whether the numbers are allowed to be repeated. If they are, there are a possible 9999 numbers, starting with 0001 and running sequentially to 9999. If they are not allowed to be repeated, there are a possible 5040 combinations.

4*3*2*1 = 24

48 of them if digits may not be repeated. 100 if they can.

6*5*4*3*2*1=720 possible numbers

There are 5! = 120 such numbers.

27 three digit numbers from the digits 3, 5, 7 including repetitions.

64 if repetition is allowed.24 if repetition is not allowed.

3*3*3*3=81

That would be 4! = 4 * 3 * 2 * 1 = 24

6*5*4*3*2*1=720

There are 5 numbers of 1 digit, 25 numbers of 2 digits, and 75 numbers of 3 digits. This makes 105 numbers in all.

-123456786

151200 numbers.

9!/(5! x 4!) = (9 x 8 x 7 x 6) / (4 x 3 x 2) =126 if all digits have to be different. If repeated digits are allowed then it is 95 ie 59049.