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As no digit is used twice then you have 4 choices for the first digit, but only 3 choices for the 2nd digit, 2 for the 3rd and just one for the 4th.

4 x 3 x 2 x 1 = 24 combinations.

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Q: How many four digit numbers can you foum from the digits 1 2 3 and 5 where no digit is used twice?
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