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โˆ™ 2010-03-03 17:26:14

Since 0-9 has 10 different digits in it, you can calculate the amount of four digit numbers (non-repeating) by multiplying 10*9*8*7. That equals 5040.

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Q: How many four digit numbers can you make using 0-9 only using each number once?
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Related questions

What is the largest 6 digit number using only even numbers using each number only once?

998,000


How many 3-digit numbers are there using 2 4 6 8 and 9?

There are 5 numbers which can make the 3 digit numbers in this example. Therefore each digit in the 3 digit number has 5 choices of which number can be placed there. Therefore number of 3 digit numbers = 5 x 5 x 5 = 125


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the place of each digit help the value of the number by using your multuplication


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This is not possible, since there are only five single digit odd numbers, which are 1, 3, 5, 7 and 9.


How many four digits numbers can be formed using 0123456789?

Assuming that the first digit of the 4 digit number cannot be 0, then there are 9 possible digits for the first of the four. Also assuming that each digit does not need to be unique, then the next three digits of the four can have 10 possible for each. That results in 9x10x10x10 = 9000 possible 4 digit numbers. If, however, you can not use the same number twice in completing the 4 digit number, and the first digit cannot be 0, then the result is 9x9x8x7 = 4536 possible 4 digit numbers. If the 4 digit number can start with 0, then there are 10,000 possible 4 digit numbers. If the 4 digit number can start with 0, and you cannot use any number twice, then the result is 10x9x8x7 = 5040 possilbe 4 digit numbers.


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The smallest number is 5,789. The largest is 98,750. The difference is 92,961.


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