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Since there are 231 cubic inches in a gallon - a simple multiplication and division problem should yield our answer.
36 in x 18 in x 17 in = 11016 in3
11016 in3 ÷ 231 in3/US gal = 47.69 US gallons.
Wiki User
∙ 11y ago
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∙ 11y agoA 16' x 16' x 32' tank can hold a maximum of about 61,280.4 US gallons.
Wiki User
∙ 9y agoIf the measurements are in feet then the volume of the tank is 35,906.49 US gallons.
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∙ 16y ago45.9 gallons.
Wiki User
∙ 7y ago60.05 US gallons.
Wiki User
∙ 11y ago27.7 Imperial gallons, approx.
Wiki User
∙ 13y ago40 gallons
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How many gallons on a 12'x16'x4' oval pool?
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448
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How many gallons of water does a rectangle hold measuring 56 inches by 18 inches?
20"x16"x12"=3840 cubic inches. 1 gal of water has a volume of 231 cubic inches therefore the nominal/quoted/rated volume of water the tank will hold is 3840 divided by 231 which is just over 16.6 gallons of water. The tank will never hold that amount of water when keeping fish. At least 1 inch will be left empty at the top and if the tank is set up with plants lights etc an average of 2 inches will be taken up with gravel at the bottom. So 3 inches is a quarter of 12 (which is the depth of the tank) that is reducing the holding capacity of the tank by one quarter so 16.6 divided by 4 will give how much less water the tank will actually hold. That amount is 4.15 gallons. So the tank will actually hold 16.60 minus 4.15 gallons. Which leaves you with 12.45 gallons if it is a planted tank. Applying the basic rule of fishkeeping "1" of fish needs a minimum of 1 gallon of water, you will see that your tank can house a maximum of 12.5 inches of fish.
How many yards of concrete to make a 20'x16'x4''?
I would say about 4.
