Previous answers http://wiki.answers.com/Q/How_much_water_will_an_18_foot_pool_by_4_feet_deep_hold
You are short one dimension. You need three dimensions to get volume, and you only gave two dimensions.
If that is 4 feet tall and 18 inches in diameter, it would be 16.83 gallons.
If this is a round pool that is 27 feet across by 52 inches tall and you fill it with 4 feet (48 inches) of water, the total volume would be 17,204 gallons of water.
A 16'x32'x52" pool holds up to 16,584gallons of water.
The pool would contain 160.43 cubic feet of water. But I'm sorry, I only speak metric so I don't know what that is in gallons.
The height of 400 gallons of water would depend on the shape of the container. 400 US gallons has a volume of about 206,000 cubic inches, so if the inside of the container was about 59 inches square, it would also be about 59 inches high.
You would use the following formula: 30 (dia.ft) X 30 (dia.ft.) X 4.66 (avg.depth.ft.) X 5.9 (multiplication factor) = 24,744.6 gallons of water
A 100-foot round pool filled with 1.5 feet of water would be holding about 88,500 gallons.
If it's round and 11 inches across on the inside, thenit can hold 579.2 ounces / 4.5 gallons full to the rim.
Depends on the depth. If it is 4 feet deep and it is cicular with a diameter of 24 feet then you have approx. 13,553 gallons of water. If it is 3 feet deep then you have approx. 10,152 gallons of water.
This container could hold up to 3,949.71 US gallons of water.
If 20' is the circumference, then the answer is 833.4 gallons.
The aquarium would have a volume of 2200 cubic inches. One cubic inch is 0.0043290 liquid gallons, so 2200*0.0043290 = 9.52381 gallons.