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70 gallons of 20% solution contains 70*0.2 = 14 gallons of antifreeze.

Suppose you need G gallons of the 80% antifreeze solution. This will contain 0.8*G gallons of antifreeze.

Total volume of solution = G + 70 gallons

Volume of antifreeze required in this solutions to make it a 70% solution is

0.7*(G + 70) = 0.7G + 49 gallons.

Volume of antifreeze = 14 + 0.8G gallons

So 0.7G + 49 = 14 + 0.8G

0.7G + 35 = 0.8G

35 = 0.1G

350 = G

Answer: 350 gallons.

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Q: How many gallons of a 80 percent antifreeze solution must be mixed with 70 gallons of 20 percent antifreeze to get a mixture that is 70 percent antifreeze?
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