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20000

Q: How many gallons of water are in a pool that is 15x25 feet and is 6 feet in deep end and 3 feet deep in shallow end?

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24,685.79 gallons

If the pool is 8 feet in the deep end and 3 feet in the shallow end, the total volume will be about 38,507 gallons of water.

10000000 gallons of water ;) it's true, my teacher told me

An in-ground pool that is 40 feet by 20 feet with the shallow end being 3ft deep and the deep end being 9ft deep has a volume of approximately 35,900 US gallons. (The depth of variable depth pools is generally calculated by adding the shallow and deep ends and dividing by two).

Length x width x average depth*. Multiply result by 7.48 to determine volume in gallons.* 'average depth' is shallow end + deep end divided by two

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Ummmmmmmmm I'm not too sure I'm bad at math.

Cannot be answered with only these measurements. You need to specify what shape the pool is. Also, for a rectangular pool, the length, width and depth are needed. For a round pool, the diameter and depth are needed.

25000 gallons

It can be shallow or deep.

40 20 4 3,200 vol 1 15 20 6 1,800 vol 2 10 20 3 0.5 300 vol 3 15 20 3 0.5 450 vol 4 sum the four volumes 5,750 cu-ft converts to 43,000 gal

24,685.79 gallons

If the pool is 8 feet in the deep end and 3 feet in the shallow end, the total volume will be about 38,507 gallons of water.

It really depends on the depth of the shallow end. However, let's say the shallow end is three feet deep. In that case, the pool holds up to about 22,980 gallons of water.

Here's a formula for round pools: distance across*distance across*depth*5.9 for rectangles: length*width*depth*7.5 or for a deep end: length*width*((shallow end depth + deep end depth)/2)*7.5 so in your case, 16*32*(3+7)/2*7.5=20000 gallons