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How many heptagons can be drawn by joining the verticles of a polygon with 10 sides?
Wiki User
∙ 10y ago
The answer is the number of combinations of 7 vertices from 10.
That is 10C7 = 10!/(7!*3!) = 10*9*8/(3*2*1) = 120.
And, there is no such word as verticles.
The answer is the number of combinations of 7 vertices from 10.
That is 10C7 = 10!/(7!*3!) = 10*9*8/(3*2*1) = 120.
And, there is no such word as verticles.
The answer is the number of combinations of 7 vertices from 10.
That is 10C7 = 10!/(7!*3!) = 10*9*8/(3*2*1) = 120.
And, there is no such word as verticles.
The answer is the number of combinations of 7 vertices from 10.
That is 10C7 = 10!/(7!*3!) = 10*9*8/(3*2*1) = 120.
And, there is no such word as verticles.
Wiki User
∙ 10y ago
Wiki User
∙ 10y agoThe answer is the number of combinations of 7 vertices from 10.
That is 10C7 = 10!/(7!*3!) = 10*9*8/(3*2*1) = 120.
And, there is no such word as verticles.
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120
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