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Q: How many hundredths in 0.638?

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At the end of the first year, the balance in the account is: 5000(1+.0638). At the end of the second year, the balance in the account is: 5000(1+.0638)(1+.0638). At the end of the third year, the balance in the account is: 5000(1+.0638)(1+.0638)(1+.0638). At the end of the t year, the balance in the account is: 5000(1+.0638)^t. So, at the end of the tenth year, the balance in the account is 5000(1+.0638)^10 = 9,280.47. $5,000 is your principal, and the remaining ($9,280.47 - $5,000) = $4,280.47 is the interest.

790 hundredths. :)

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