How many is G2 in Graham's Number?

Answer 1

g1 = 3 ↑↑↑↑ 3

g2 = 3 ↑↑......g1 arrows......↑↑3

g3 = 3 (g2 arrows) 3

etc...

g1 = 3 ↑↑↑↑ 3 = 3 times 3 in 3 ↑↑↑ 3 = > This is 3 ↑↑↑ 3 ↑↑↑ 3 -> this is: 3 ↑↑↑ (3 ↑↑↑ 3)

Now, lets do the ( ) first:

3 ↑↑↑ 3 = 3↑↑3↑↑3 = 3↑↑(3↑↑3)

We have to go back once more:

from that 3↑↑(3↑↑3)

to that: 3↑↑3

3↑↑3 = 3 ↑ (3 ↑ 3) = 3^(3^3) = 3^27 = 7.625.597.484.987

Then the next step:

3↑↑(7.625.597.484.987) = a power tower of 7.625.597.484.987 3s where you have to go from the top to the bottom:

Imagine this Power tower and lets just calculate from the top:

3^3 = 27

3^27 = 7.625.597.484.987

3^7.625.597.484.987 = a big number, (I've calculated it: ~ more than 200 pages A4 with small letters . the number has approx.~ 6.9 x 10^6 digits

My problem is: how would I name such a big number, there is no name for it yet, and it's a big way bigger than 10^600 which is called centillion I think, I haven't found a way tpo name that number. Should I simply call it A number for a step for Grahams numbers? How do I get a real name for this number?