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Power = V x A = 6 x 0.5 = 3 watts = 3 joules per second

dissipated by the lamp into the surrounding environment

in the form of heat and light.

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12y ago
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1mo ago

The power output of the lamp can be calculated using the formula P = V * I, where P is power (in watts), V is voltage (in volts), and I is current (in amperes). For the lamp with 6V and 0.5A, the power output would be 3 watts. One watt is equal to 1 joule per second, so the lamp is transferring 3 joules of electrical energy per second.

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Q: How many joules of electrical energy is transferred per second by 6V 0.5 A lamp?
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