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How many joules of electrical energy is transferred per second by 6V 0.5 A lamp?

Updated: 5/29/2024

Wiki User

12y ago

Power = V x A = 6 x 0.5 = 3 watts = 3 joules per second

dissipated by the lamp into the surrounding environment

in the form of heat and light.

Wiki User

12y ago

1d ago

The power output of the lamp can be calculated using the formula P = V * I, where P is power (in watts), V is voltage (in volts), and I is current (in amperes). For the lamp with 6V and 0.5A, the power output would be 3 watts. One watt is equal to 1 joule per second, so the lamp is transferring 3 joules of electrical energy per second.

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Q: How many joules of electrical energy is transferred per second by 6V 0.5 A lamp?
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