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How many liters of a 20 percent alcohol must be mixed with 40 liters of a 90 percent solution to get a 60 percent solution?
Wiki User
∙ 11y ago
Let L be the liters to be added. Then
(L) x (0.2) + (40 x 0.9) = (L + 40) x 0.6
0.2L + 36 = 0.6L + 24
36 - 24 = (0.6 - 0.2)L
12 = 0.4L
L = 12/0.4 = 120/4 = 30 Liters
Wiki User
∙ 11y ago
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