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The container is a cylinder. Its volume = pi R2 L = (pi) (1.5m)2 (3m) = 21.206 m3 (rounded)

1 m3 = 1,000 litres

To fill the 3m x 3m tank to the rim takes 21,206 litres(rounded)

Q: How many liters to fill a 3m diameter x 3m deep circular container?

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There are 3,634 liters (960 gallons) of water in a pool that is four feet in diameter and 8 feet deep.

About 530.14 litres This container is a cylinder. Volume_of_cylinder = π x radius2 x depth. radius = diameter ÷ 2 = 1500 mm ÷ 2 = 750 mm 1 litre = 1000 cm3 = 1000000 mm2 ⇒ volume = π x (750 mm)2 x (300 mm) = 168750000π mm3 = 168750000π ÷ 1000000 litres = 168.75π litres ≈ 530.14 litres

About 28,944.8L

Assuming a circular pool, divide the diameter by 2 to get the radius, then use the formula for the area of a circle. The depth is not relevant for this problem.

If the 24' is the circumference (distance around the outside), then: Diameter = Circumference / pi = 7.6394 ft.Radius = Diameter / 2 = 3.8197 ft.Area = pi * radius^2 = 45.8366 sq. ft.Volume = A * depth = 206.2648 cu. ft. = 5841.42 liters (because 1 cubic ft = 28.32 liters). If the 24' is the diameter, then your numbers are: Radius = 12'Area = 452.39 sq. ft.Volume = 2035.75 cu. ft. or 57652.5 liters.

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There are 3,634 liters (960 gallons) of water in a pool that is four feet in diameter and 8 feet deep.

About 530.14 litres This container is a cylinder. Volume_of_cylinder = π x radius2 x depth. radius = diameter ÷ 2 = 1500 mm ÷ 2 = 750 mm 1 litre = 1000 cm3 = 1000000 mm2 ⇒ volume = π x (750 mm)2 x (300 mm) = 168750000π mm3 = 168750000π ÷ 1000000 litres = 168.75π litres ≈ 530.14 litres

About 28,944.8L

Less than one if the container is very shallow, and more than thousands, if the container is deep enough.Less than one if the container is very shallow, and more than thousands, if the container is deep enough.Less than one if the container is very shallow, and more than thousands, if the container is deep enough.Less than one if the container is very shallow, and more than thousands, if the container is deep enough.

Assuming a circular pool, divide the diameter by 2 to get the radius, then use the formula for the area of a circle. The depth is not relevant for this problem.

A 3 inch diameter by 3 inch high container is 21.195 cubic inches. There is 1.805 cu in per ounce, so that would be 21.195/1.805 = 11.74 ounces

My swimming pool holds 1250 gallons. It is 12 feet diameter and 3 feet deep.

Victorian bath-tubs were not circular, so they did not have a diameter. They were usually about 2 feet wide (60 cm) and about 5 feet long (1.5 m) and 2.5 feet (75 cm) deep.

If the 24' is the circumference (distance around the outside), then: Diameter = Circumference / pi = 7.6394 ft.Radius = Diameter / 2 = 3.8197 ft.Area = pi * radius^2 = 45.8366 sq. ft.Volume = A * depth = 206.2648 cu. ft. = 5841.42 liters (because 1 cubic ft = 28.32 liters). If the 24' is the diameter, then your numbers are: Radius = 12'Area = 452.39 sq. ft.Volume = 2035.75 cu. ft. or 57652.5 liters.

As deep as the container in which the water is in

The volume 10 foot times 5 foot times 2 foot is 100 cubic feet. 100 cubic feet are 2831.6846592 liters.

Assuming the pool is circular, and that you fill the pool to the brim, the pool will contain about 2028 liters of water. However, if you want to leave 4 inches for the water to have some room to splash around, that'll cut that number down to 1859 liters.