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Multiples of 8 between 0-100?
16,24,32,40,48,56,64,72,80,88,96
How many numbers between 0 and 100 are divisible by both 6 and 8 and what are the numbers?
Four. 24 and its multiples.
How many prime numbers are between 0-100?
100
How many numbers between 0 and 100 are divisible by 4?
Since 100/4 = 25, there are 25 numbers between 0 and 100 divisible by 4.
What is 37000 divided by 100?
370
Multiples of 8 between 0-100?
16,24,32,40,48,56,64,72,80,88,96
How many multiples of 17 are there between 0 an 100?
17, 34, 51, 68, 85
How many numbers between 0 and 100 are divisible by both 6 and 8 and what are the numbers?
Four. 24 and its multiples.
How many numbers between 0 and 1000 are divisible by 6 or 10?
There are 166 multiples of 6 in that range. There are 100 multiples of 10 in that range. There are 33 numbers on both lists. 266 - 33 = 233
How many numbers are there between 0 and 100?
There are 99 numbers between 0 and 100.
How many prime numbers are between 0-100?
100
What is the multiples of 10 between 0 and 101?
10, 20, 30, 40, 50, 60, 70, 80, 90, 100
How many multiples of 6 are there between 0 and 25?
There are four: 6, 12, 18, 24.
How many numbers between 0 and 100 are divisible by 2?
49 if you don't include 0 and 100. 51 if you include 0 and 100.
How many numbers between 0 100 are divisible by 7?
There are a total of 14 numbers between 0 & 100 that are divisible by 7.
How do you write a C program using an integer array to print array numbers up to 100 and then remove all numbers that are divisible by 2 and print out the remaining numbers and continue for 3 to 9?
#include<stdio.h> #include<conio.h> void main() { int i, a[100]; clrscr(); printf("Numbers from 1 to 100"); for(i=1;i<=100;i++) printf(" %d",a[i]); printf("Numbers from 1 to 100 without multiples of 2"); for(i=1;i<=100;i++) { if (a[i]%2 !=0) printf(" %d",a[i]); } printf("Numbers from 1 to 100 without multiples of 3"); for(i=1;i<=100;i++) { if (a[i]%3 !=0) printf(" %d",a[i]); } printf("Numbers from 1 to 100 without multiples of 4"); for(i=1;i<=100;i++) { if (a[i]%4 !=0) printf(" %d",a[i]); } printf("Numbers from 1 to 100 without multiples of 5"); for(i=1;i<=100;i++) { if (a[i]%5 !=0) printf(" %d",a[i]); } printf("Numbers from 1 to 100 without multiples of 6"); for(i=1;i<=100;i++) { if (a[i]%6 !=0) printf(" %d",a[i]); } printf("Numbers from 1 to 100 without multiples of 7"); for(i=1;i<=100;i++) { if (a[i]%7 !=0) printf(" %d",a[i]); } printf("Numbers from 1 to 100 without multiples of 8"); for(i=1;i<=100;i++) { if (a[i]%8 !=0) printf(" %d",a[i]); } printf("Numbers from 1 to 100 without multiples of 9"); for(i=1;i<=100;i++) { if (a[i]%9 !=0) printf(" %d",a[i]); } getch(); }
What fraction of the numbers from 0 to 100 are multiples of 10?
Numbers from 0 to 100 that are multiples of 10 are: 10, 20, 30, 40, 50, 60, 70, 80, 90, 100. That's ten numbers, so the fraction of numbers from 1 to 100 that are multiples of 10 is 10/100. In simplest form it is 1/10.
