numbers between 100 and 1000 = 900
numbers between 100 and 1000 which do not have digit 6 in any place = 8 x 9 x 9 = 648
Unit digit could take any value of the 9 values (0 to 9, except 6)
Tens Digit could take any value of the 9 values (0 to 9, except 6)
Hundreds digit could take any value of the 8 values (1 to 9, except 6)
numbers between 100 and 1000 which have atleast one digit as 6 = 900 - 648 = 252
123
Not couting 1 and 1000, there would be 998 numbers.
252 of them.
16
91.
solution: we know that there are 25 prime numbers are between 1-100 and 168 prime numbers less than 1000. 100 x 100=10000(5 digits) 999 x 999=998001(6 digits) 1000 x 1000=1000000(7 digits) so our answer should be same as the number of prime numbers between 100 to 999. hence, 168-25=143. 143 prime numbers will be there less than 1000 whose square has 5 or 6 digits.
it s 243..
11000
Zero
999 are whole.
Numbers above 99 and under 1000 are 3-digits, all 900 of them.
1,234,567 2,345,678 3,456,789