1, 2, 4, 7, 14, and 28 are the numbers that match this description. Therefore, six numbers divide into it evenly.
7.6429
1.3333
28 out of 98 may be divided by two to get 14 out of 49. Those numbers can each be divided by seven, to give us 2 out of 7. There being no further number (besides 1) that can divide into each of those numbers with no remainder, your answer is "2 out of 7".
There are 10 numbers between 10 and 80 that are divisible by 7 with no remainder: 14, 21, 28, 35, 42, 49, 56, 63, 70, and 77.
Just add the numbers. Then divide the result by "how many numbers are there", in this case, 6.
3 can't divide into anything and leave a remainder of 28. If you divide 43 into 157, the answer is 3, with a remainder of 28.
The largest number that will divide into 28 42 and 70 with no remainder is 14.
Because they are the only numbers that will divide evenly into both 28 and 32 with no remainder.
4.6667
Because 3 doesn't divide evenly into 28 with no remainder.
The GCF is 4, because it's the largest positive integer that can divide into both numbers evenly with no remainder.
28. It is always one less than the divisor.
7.6429
These are the numbers that divide into 28 evenly: 1, 2, 4, 7, 14, 28.
If you take four consecutive numbers, for example, 27, 28, 29, and 30, then 27/3 = 9, 28/3 = 9 remainder 1, 29/3 = 9 remainder 2, 30/3 = 10. Therefore, the greatest remainder you can get when dividing by 3 is 2.
872 divided by 31 is 28.129 or 28 with remainder 4.
1.3333