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The number of odd numbers in the Nth row of Pascal's triangle is equal to 2^n, where n is the number of 1's in the binary form of the N. In this case, 100 in binary is 1100100, so there are 8 odd numbers in the 100th row of Pascal's triangle.

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โˆ™ 2014-09-17 21:13:27
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Q: How many odd numbers are in the 100th row of Pascals triangle?
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Yes. I think they're in the 3rd diagonal of the triangle. Basically, its how many numbers you need to make a geometrically correct triangle: 1, 3, 6, 10......

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There is actually no limit to the number of numbers in Pascal's Triangle. The triangle is simply a way to remember the coefficients of the product of two binomials (or the expansion of a binomial raised to a power). See the link below. The triangle starts like this: 1 1 1 1 2 1 1 3 3 1 1 4 6 4 1 It goes on forever. Simply begin and end each row with a one and find the numbers in the middle by adding the two above it. Edit: I don't know how to make the above triangle look correct here. The program wants to remove all of the spaces, making the triangle look like a right triangle. Just ignore that. It should look like a pyramid, with the top 1 in the center.

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