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Q: How many ounces of a ten percent alcohol solution must be mixed with 6 ounces of a fifteen percent alcohol solution to make a thirteen percent alcohol solution?
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Related questions

What is fifteen percent of thirteen?

15% of 13 is 1.95


The concentration of alcohol and water solution is 25 percent alcohol by volume what is volume of alcohol and 200 lM of solution?

If the concentration of alcohol and water solution is 25 percent alcohol by volume, the volume of alcohol in a 200 solution is 50.


6 pints of a 20 percent solution of alcohol in water are mixed with 4 pints of a 10 percent alcohol in water solution What is the percentage alcohol in the new solution?

16%


What is fifteen percent of thirteen thousand?

195015% of 13000= 15% * 13000= 0.15 * 13000= 1950


What is a 60 percent isopropyl alcohol?

This is a solution containg 60 percent isopropyl alcohol; can be used as rubbing alcohol.


What is the thirteen percent of fifteen thousand dollars?

13% of $15,000.00= 13% * 15000= 0.13 * 15000= $1,950.00


What is the volume of alchol in 200ml of a solution if it is 20 percent?

200ml of solution x 20% of alcohol = 40ml of alcohol..


How many liters of 10 percent alcohol solution must be mixed with 70 liters of a 70 percent solution to get a 30 percent solution?

210Type your answer here...


How many milliliters of alcohol are in 167 ml of an 85.0 percent alcohol solution?

141.95


How many ounces of 15 percent percent alcohol must be mixed with 23 percent alcohol solution to make 100 ounces?

That all depends on what you want the final concentration of alcohol to be.


How many ounces of a 25 percent alcohol solution must be mixed with 9 ounces of a 30 percent alcohol solution to make a 28 percent alcohol solution?

Let a be the number of ounces of 25% alcohol required. Then, 25a + (30x9) = 28(9 + a) 25a + 270 = 252 + 28a 3a = 18 a = 6 Then 6 ounces of 25% alcohol + 9 ounces of 30% alcohol produces 15 ounces of 28% alcohol.


How many ounces of the 50 percent alcohol solution should be mixed with the 1 percent alcohol solution to make 8 oz of the 20 percent alcohol solution?

Let x = ounces of 50% solution, and y = ounces of 1% solution. So that we have: 0.5x + 0.01y = 8(0.2) which is a linear equation in two variables, meaning there are infinitely many choices of mixing those solutions.