Infinitely many. The answer depends onhow many times the experiment is repeated.
Infinitely many. The answer depends onhow many times the experiment is repeated.
Infinitely many. The answer depends onhow many times the experiment is repeated.
Infinitely many. The answer depends onhow many times the experiment is repeated.
Infinitely many. The answer depends onhow many times the experiment is repeated.
The sum of the probabilities of all possible outcomes is 1.
All possible outcomes: 2,3,4,5,6,7,8,9,10,11,12 All possible outcomes that are prime: 2,3,5,7,11 All possible rolls that are one of these prime numbers: --1-2-3-4-5-6 1.*.*....*....* 2.*....*....*... 3....*....*...... 4.*....*......... 5....*..........* 6.*..........*... So we count 15 possible ways to make a prime number. P = (# of correct outcomes) / (# of total possible outcomes) P = 15 / (6*6) = 0.416667 or 5/12
Just 1.
There are 24 = 16 ordered outcomes, that is outcomes in which the order of the results is relevant. If not, there are 5 outcomes (0 heads, 1 head, 2 heads, 3 heads and 4 heads).
Number of useful outcomes over number of possible outcomes and simplify it if you can. Imagine you want an even number and you roll a die. There are 6 possible outcomes and three of them are useful outcomes (outcomes we want). 3 6 Simplify it and you get 1 2
Six.
36 possible outcomes, assuming replications (ie: rolling a 6 and a 1, rolling a 1 and a 6; counted as two separate outcomes.)
Number of possible outcomes = 6Number of outcomes that are odd numbers = 3P = 3/6 = 50% .
-8
Six.
The outcomes are: heads, tails, tails or tails, heads, tails or tails, tails, heads. You can see that there are 3 possible outcomes with exactly 1 head.
The sum of the probabilities of all possible outcomes is 1.
There are 210 total possible outcomes from flipping a coin 10 times.There is one possible outcome where there are 0 heads.There are 10 possible outcomes where there is 1 head.So there are 210 - 11 possible outcomes with at least 2 heads.(1013)
Depends on how many numbers are on each cube. Say one has m numbers and the other has n numbers, you can get mxn outcomes.* * * * *This could get rather complicated!By definition, a cube has only six faces and so each die can have only six numbers on it. BUT, these numbers need not all be different.If they are all different then m = n = 6 and there are 36 outcomes in all.More generally, a single die can have6 outcomes (6 numbers each appearing once)5 outcomes (4 numbers singly and 1 pair)4 outcomes (3 numbers singly and 1 triple or 2 singles and 2 pairs)3 outcomes (2 singles and 1 quartet or 1 single and 1 pair and 1 triple or 3 pairs)2 outcomes (1 single and 1 quintet or 1 pair and 1 quartet or 2 triplets)1 outcome (1 sextet).So m can have any of the six values 1,2,3,4,5,6. And similarly, so can n.And therefore, m*n can have the following values:1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 12, 15, 16, 18, 18, 20, 24, 25, 30, 36.
1,2,3,4,5,6 are the possible outcomes. There's a 1/6 chance for each.
All possible outcomes: 2,3,4,5,6,7,8,9,10,11,12 All possible outcomes that are prime: 2,3,5,7,11 All possible rolls that are one of these prime numbers: --1-2-3-4-5-6 1.*.*....*....* 2.*....*....*... 3....*....*...... 4.*....*......... 5....*..........* 6.*..........*... So we count 15 possible ways to make a prime number. P = (# of correct outcomes) / (# of total possible outcomes) P = 15 / (6*6) = 0.416667 or 5/12
The probability of an event is the number of favourable outcomes divided by the total number of possible outcomes. What is the total number of possible outcomes of tossing a number cube? 6 How many outcomes are favourable to the event of getting a five? 1 So the prob is 1/6 or 0.16667