If you include negative numbers, the list is infinite.
The numbers are 18 and 20.
224 x 226
I would list all the factors of 480 (as pairs of numbers whose product is 480). Then find two pairs of numbers (L1,W1 and L2,W2) satisfying these properties. (It won't take long, since there are at most sqrt(480) (rounded down) pairs of numbers whose product is 480, ie. just try the numbers 1,2,3,...,21.) Hope that helps!
The numbers are 2, 4 and 6.
Divide 126 by 2 and choose the even numbers on both sides.
100
There are two pairs of even numbers that satisfy the condition. They are (8, 10) and (6, 12).
no
It means write down three pairs of numbers that are relatively prime like 4 and 9, 5 and 6, 13 and 25
The numbers are 18 and 20.
The numbers are 272 and 274.
I think of factor pairs of 24, like 8 and 3, that add up to 11.
Infinitely many. However, if you don't want negative numbers, the lower of the two numbers must be at least 0, and at most 22. The higher of the two numbers, of course, will be 46 minus the first number. Perhaps you can work it out from there.
They are 16 and 18
Assuming the question concerns numbers whose SUM is 192, the answer is 62, 64 and 66.
-- There are 11 even numbers that are less than 1/2 of 46. -- Each of those can be paired with another even number that is more than 1/2 of 46. -- So there are 11 possibilities.
10 and 12