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Q: How many pairs of prime numbers are consecutive natural numbers between 1 and 100?

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The numbers 2 and 3 are consecutive prime numbers. Are there other pairs of prime numbers which are consecutive numbers?

Yes there is there should be!

Consecutive whole numbers are integer pairs of the form n and n+1. There can be no integer, such as 110, between such numbers.

(5,6) (6,7) (14,15)

2 and 3

Adding consecutive pairs of numbers will always turn out to be an odd number. It would have to be consecutive odd numbers: 45 and 47.

Consecutive numbers implies integers. Rational or real numbers are infinitely dense so there is no "next" number. There can be no pairs of integers such that their product is a fractional number between 559 and 560.

There are many pairs of consecutive whole numbers that lie between the square roots of 46, which are approx -6.78 and +6.78. -4 and -3, for example.

The only pair is 2 and 3.

Pick any two consecutive numbers in that range.

Pick any two consecutive numbers in that range.

The factor pairs of 1295 are (1295,1)(259,5)(185,7)(37,35) None of them are consecutive. 35 and 37 are consecutive odd numbers.

There are infinitely many such pairs. The first pair is 8 and 9.

Although not specified as such, "consecutive" requires the numbers to be integers. Two pairs literally means four numbers but there are not four consecutive integers that add up to to 5280. 1318 + 1319 + 1320 + 1321 = 5278 and 1319 + 1320 + 1321 + 1322 = 5282. Four consecutive numbers must add up to an even number that is not a multiple of 4. If by two pairs, the question meant ONE pair (!!), again there is no answer since the sum of any pair of consecutive numbers must be an odd number.

4 and 5 5 and 6 Any consecutive integers greater than one.

The only two consecutive numbers that are both prime are 2 and 3. Since there are no other even prime numbers (other than 2), there are no more pairs of consecutive prime numbers. Therefore, the term "twin primes" usually refers to pairs of prime numbers that are 2 numbers apart. Examples are (3, 5), (5, 7), (11, 13), (101, 103), and many others more. It is not currently know whether there are infinitely many twin primes.

There are an infinite number of prime numbers which are consecutive odd integers. Choose any natural number n. Take all primes up to any number n, take their product, and add 1 and subtract 1 from it. These 2 numbers are consecutive odd integers. eg 2*3*5*7 = 210 209 and 211 are primes which are consecutive odd integers.

(3,5), (5,7), (11,13), (17,19) plus infinitely more.

The GCF is 1. Anytime there are two consecutive integers, their GCF will be 1.

The difference between the squares of two consecutive integers j and j+1 is |2j+1|. There are therefore two such pairs where this quantity is 17:-9 and -88 and 9

80 has 5 factor pairs.

There are 35 pairs of twin prime numbers totaling 69 numbers (prime number 5 appears twice in the twin pairs) between 0 and 1000.

Ah hah! You didn't say so, but you must be talking about 2 and 3 ... the only two consecutive numbers that are both prime numbers. There can't be any others. Because if you have any other two consecutive numbers, one of them has to be an even number ... divisible by 2. Since that number is divisible by 2, it's not a prime number.

There is only one pair of consecutive prime numbers, and the prime numbers are two and three, because any pair of consecutive numbers has one odd and one even number, and two is the only even prime number, because all other even numbers can be divided by two, and the only pairs of consecutive numbers are one and two and three, but one is not prime because it only has one factor, thus making the only consecutive pair of primes two and three. But the problem asks for the product of the two numbers, not the numbers themselves, so just multiply two and three together to get a final result of six.

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