There are infinitely many such product pairs.
There are 8 different pairs of whole numbers whose prodcut is 40. Allowing for commutativity (a*b = b*a), there are 16 possible ways.
4, if you multiply them.
20 of them
The prime factors of 333 are 3,3 and 37 Thus the pairs of whole numbers that go into 333 are: 1 and 333 3 and 111 9 and 37 There are 3 pairs.
There are infinitely many pairs. One such is 1 and 98.
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An infinite number.
Eight has two factor pairs. Including their negative counterparts, that makes four pairs.
3 pairs of whole numbers add up to 7: 1 +6, 2+5, 3+4 (0+7 also equals 7, but zero is not a whole number)
There are infinitely many pairs. One such is 288 and -1.
A single number does not have a product. there are infinitely many pairs (or sets of more numbers) whose product is 21. For example, 210 and 0.1
3 pairs 1 times 12, 2 times 6, and 3 times 4
8 and 12 . There are many other pairs of words whose product is 96.
An infinite amount if you add, subtract or divide them. 3 pairs if you multiply them.
10x5 and 1x50
There are many pairs of numbers that add of to 64. One is (1,63), and the product is 63. Another is (2,62), and the product is 124. There seems to be something missing from the question, perhaps some constraint on the product. Please restate the question.
Three pairs of integers alone have this property: 12 and 1; 2 and 6; and 3 and 4. There are infinitely many non-integer pairs also.
If there are n numbers in the group, there aren2 ordered pairs if the numbers can be repeated,n*(n-1) ordered pairs if the numbers cannot be repeated,n2/2 pairs if the numbers can be repeated,n*(n-1)/2 pairs if the numbers cannot be repeated.
There are many pairs of consecutive whole numbers that lie between the square roots of 46, which are approx -6.78 and +6.78. -4 and -3, for example.
An infinite number of times. If you restrict yourself to whole numbers, 500 has 6 factor pairs.
2. 4 if you include negatives.