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11, 22, 33, 44, 55, 66, 77, 88, 99

That's 9

101, 111, 121, 131, 141, 151, 161, 171, 181, 191

That's 10

202, 212, 222, 232, 242, 252, 262, 272, 282, 292

That's 10

Total of 29

Unless 0 - 9 are considered palindromes also.

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Q: How many palindromes are between 0 and 300?
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How many palindromes are between 0 and 1000?

109


How many palindromes are there between 0 and 1?

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Find the number of integer palindromes between 10000 and 99999 that are divisible by 25?

All palindromes between 10000 and 99999 are of the form abcba where a is a digit in {1, 2, ..., 9} and b and c are digits in {0, 1, ..., 9} All multiples of 25 end in 00, 25, 50 or 75. As a cannot be 0, this means the only multiple of 25 we are interested in are those which end in 25 and 75. This means we are looking for integers of the form 52c25 and 57c75. There are 10 possible values for the digit c in each case (one of {0, 1, ..., 9}), which means: There are 20 palindromes between 10,000 and 99,999 which are divisible by 25.


How many times does the digit 0 appear between 1 to 300?

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0