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Q: How many people are at a party with 741 handshakes if everyone shakes once?
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If at a party there are a total of 741 handshakes and each person shakes hands with everyone else at the party exactly once how many people are at the party?

38


If there are 8 people at a party and every person shakes hands with everyone else at the party how many handshakes will there be?

There will be 28 handshakes. If you ask each person how many handshakes they had they will tell you 7 making 7 x 8 = 56 handshakes in all. But every hand involves two people, so every handshake has been counted twice, thus there are 56 / 2 = 28 handshakes in all.


If ten people are at a party and they all exchange handshakes how many hand shakes were exchanged?

If that happens you have to times ninexten and the answer would be 90 handshakes


Seve girls arrive at a tea party each of them shakes hands once with each of the others how many handshakes does that make?

21 handshakes


Seven people come to a party and shakes hands with each other if each person shakes the hand of every other person how many hand shakes occur?

If there are seven people, then the number of handshakes is 7*6/2 = 21


If at a party there are twelve people present Everyone has to shake hands exactly once with every other person How many handshakes are necessary?

Sixty-six unique, distinct handshakes.


At certain party there wereb 45 handshakes Everyone shook hands with everyone else exactly once how many people attended the party?

There were ten people at the party. This is a triangular sequence starting with two people: 1, 3, 6, 10, 15, 21, 28, 36, 45, etc. There's an equation for this. With n people at the party, the number of handshakes is n(n-1)/2.


If ten people met at a party and they all exchanged handshakes how many handshakes were exchanged?

107 unique handshakes will be exchanged


In a party everyone shakes hand with each other. If total number of handshakes is 780 how many people were there?

There were 40 people at the party. Let n be the number of people at the party. Each person shakes hands with every other person, so each person shakes hands with (n - 1) people, a possible total of n(n - 1) handshakes. But when person A shakes hands with person B, B also shakes hands with A, so each handshake would be counted twice. → number_of_handshakes = n(n - 1)/2 total number of handshakes is 780 → n(n - 1)/2 = 780 → n(n - 1) = 1560 → n^2 - n - 1560 = 0 As 1560 is negative, one factor is positive and one is negative, so we need the factor pair of 1560 which has a difference of 1, namely: 39 x 40 → (n - 40)(n + 39) = 0 → n = 40 or -39 There cannot be a negative number of people → there are 40 people present.


there are 3 people at a party if each person mis shake hands with every person at the party exactly once how many handshakes will there be?

So, there will be 3 handshakes among the 3 people at the party.


If there 28 handshakes how many people are at the party?

29 People including You.


There are 3 people at a party If each person must shake hands with every other person at the party exactly once how many handshakes will there be?

With 3 people, there are only 3 handshakes: AB, AC, and BC. Where it gets interesting is at a party with, say, 10 people ... 45 handshakes. Or in the US Senate when all 100 Senators are present ... 4,950 handshakes.