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Assuming that each person shakes hands with every other person, there are 12 people.

Let n be the number of people.

Then each person shakes hands with (n-1) people and if you ask every person how many hand shakes they made and total them you will get a total of n(n-1) handshakes.

However, each handshake involves two people and has been counted twice - once by each person that shook hands - thus number of hand shakes is half of this, giving:

n(n-1)/2 = 66

⇒ n(n-1) = 132

⇒ n2 - n - 132 = 0

⇒ (n - 12)(n + 11) = 0

⇒ n = 12 or -11

You can't have -11 people, therefore there are 12 people.

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Q: How many people are there if everyone shakes hands and there are 66 handshakes?
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