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How many possible 5 number combination numbers1-9 without using same number twice?
Wiki User
∙ 12y ago
Any 5 from 9 = (9 x 8 x 7 x 6)/(4 x 3 x 2) = 126
Any 5 in any order = 5 x 4 x 3 x 2 = 120
Answer: 126 x 120 = 15120
Wiki User
∙ 12y ago
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