If my math is correct it would take an additional ( .6 of a U.S. quart of
antifreeze ) to increase a 30 % antifreeze volume to 40 % if the total
volume of the mixture is 6 quarts
4.2 quarts
(X gal)(0.15) = (1 gal)(0.025)0.15X = 0.025X = 0.17 gallons (4 quarts/1 gal.)(1 liter/1.06 quarts)(1000 ml/1 liter)= 642 milliliters============
If 'X' is the number of quarts of 6 percent butterfat milk and 'Y' is the number of quarts of the 1 percent butterfat milk then: x + y = 75 quarts and (6x + 1y)/75 = 4 (because we want 4 percent per quart) then solving for the system of equations leads to: x = 45 quarts (the 6 percent) and y = 30 quarts (the 1 percent)
20% of 12 quarts= 20% * 12= 0.2 * 12= 2.4 quarts or 76.8 ounces (US measure)
approximately 4.02 US quarts = 3.8L Solution Method: Known Conversion Fact: 1 liter = 1.05668820943259377 US quarts therefore: 3.8L * 1.05668820943259377 US quarts/Liter = 4.015415195843856326 qts
The original solution has 3.6 quarts of antifreeze in it. The equation then becomes (3.6 + x)/(12 + x) = 0.40, where x is the amount of antifreeze added. X is then equal to 2.
4.2 quarts
You need 1 1/3 quarts of pure antifreeze.
In the original solution, you have 5 quarts total, 20% antifreeze. So 20% * 5 = 1. You have 4 qt water and 1 qt antifreeze. You will add an amount A, to this mixture. When you add, the new total volume (in quarts) is 5 + A, and the percentage is:(1 + A)/(5 + A) x 100%. So when you start out at A = zero, you have 1/5 x 100% = 20%.So set up the equation (1 + A)/(5 + A) * 100 = 30, and solve for A.Multiply both sides by (5+A) and isolate the term A. Note that since you are adding, the value of A will never be negative (so you don't have to worry about the denominator (5+A) being zero.Answer = 5/7 (quarts) = 0.714285714285155 quarts.
I'd go buy a bottle of pre-mixed antifreeze, and just fill it up with that. Less hassle, works great.
4 quarts or one gallon of pure antifreeze, mixed with an equal amount of distilled water, for a 50/50 mix.
30 quarts of 2 percent 15 quarts of 5 percent
9.1 US quarts
(X gal)(0.15) = (1 gal)(0.025)0.15X = 0.025X = 0.17 gallons (4 quarts/1 gal.)(1 liter/1.06 quarts)(1000 ml/1 liter)= 642 milliliters============
For the 2003 Ford Ranger with a 3.0 liter V6 engine and AUTOMATIC transmission ( 7.4 quarts of antifreeze ) * That's for a 50 / 50 mix of 7.4 quarts of antifreeze and 7.4 quarts of preferably distilled water * because the engine cooling system capacity is 14.8 quarts according to the owners manual
For a 1987 Mercury Grand Marquis : For the 5.0 liter / 302 cubic inch V8 engine ( 7.5 quarts of antifreeze with 7.5 quarts of preferably distilled water should give you a 50 / 50 mix of engine coolant ) --------------------------------------------------------------------------- For the 5.8 liter / 351 cubic inch ( 8.0 quarts of antifreeze )
2 gallons of non-toxic antifreeze