357 * 49 / 7 = 2499
To find how many 7s are in the product of 357 and 49, we first calculate the product: (357 \times 49 = 17,493). Next, we determine how many times 7 can fit into 17,493 by dividing: (17,493 \div 7 = 2,499). Therefore, there are 2,499 instances of 7 in the product 357 and 49.
To find how many 7s are in the product of 357 and 49, we first calculate the product: ( 357 \times 49 = 17,493 ). Next, we need to determine how many times 7 divides evenly into 17,493. Dividing, we find that ( 17,493 \div 7 = 2,498.71 ), which means there are 2 complete 7s in the product. Thus, the product contains 2 full 7s.
49 metre because seven sevens = 49
7*7 + 7 - 7 is one of many ways to do this.
Answer 6Here is why:7x7=49 which is 1 too many, so there are six sevens in 48 with a remainder of 6.
To find how many 7s are in the product of 357 and 49, we first calculate the product: (357 \times 49 = 17,493). Next, we determine how many times 7 can fit into 17,493 by dividing: (17,493 \div 7 = 2,499). Therefore, there are 2,499 instances of 7 in the product 357 and 49.
There are: (357*49)/7 = 2499
To find how many 7s are in the product of 357 and 49, we first calculate the product: ( 357 \times 49 = 17,493 ). Next, we need to determine how many times 7 divides evenly into 17,493. Dividing, we find that ( 17,493 \div 7 = 2,498.71 ), which means there are 2 complete 7s in the product. Thus, the product contains 2 full 7s.
7
there are 343 sevenths in 49 not 7 because it says sevenths not sevens.
49 metre because seven sevens = 49
7*7 + 7 - 7 is one of many ways to do this.
Answer 6Here is why:7x7=49 which is 1 too many, so there are six sevens in 48 with a remainder of 6.
42, 49, 56, 63, 70.....
There are seven sevens in fifty, as 50 divided by 7 equals approximately 7.14. This means that seven multiplied by 7 equals 49, which is the largest multiple of seven that fits into fifty. Thus, the whole number of sevens in fifty is seven.
700 decreased by 49 percent = 357
7