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Q: How many sides does a polygon have if each exterior angle of a regular polygon is 15?

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With a regular polygon: 360/exterior angle = number of sides

Exterior angle regular polygon = 360° ÷ number of sides = 360° ÷ W Interior angle regular polygon = 180° - exterior angle regular polygon = 180° - (360° ÷ number of sides ) = 180° - (360° ÷ W)

360/number of sides = exterior angle

360/exterior angle = number of sides of a regular polygon

A regular polygon with an exterior angle of40O is a nonagon, and has 9 sides.

A regular polygon that has an exterior angle of 60 degrees = 360/60 = 6 sides and it is an hexagon

A regular polygon will have 360 sides with exterior angles of 181 degrees.

360/number of sides = exterior angle

360/number of sides = exterior angle

Each exterior angle is 15 degrees

5 sides, a regular pentagon.

60

By dividing the given exterior angle into 360 degrees tells you how many sides the polygon has.

Providing that it is a regular polygon it will have 8 sides.

By dividing number of its sides into 360 will give you the exterior angle.

exterior angle of regular polygon is always 360 divided by number of sides, so number of sides = 360 divided by exterior angle, in this case 360/32.72 ie 11.

180-interior angle = exterior angle If it's a regular polygon then: 360/number of sides = exterior angle

If those are exterior angles, the exterior angles of any polygon add up to 360. That would be 20 sides.

If those are exterior angles, the exterior angles of any polygon add up to 360. That would be 18 sides.

8

15 sides

12 sides

It has 360/20 = 18 sides

360/number of sides

The sum of the exterior angles of a regular polygon equal 360° . If one such angle measures 36° then the polygon has 360/36 = 10 sides.