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Q: How many sides does a polygon with n vertice have?

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An n-sided polygon or n-gon, just like it sounds, has n sides. For example, a 13-sided polygon has 13 sides. A 24-gon has 24 sides.

That depends on how many sides the polygon has but in general the number of degrees inside a polygon are: (n-2)*180 = sum of degrees whereas 'n' is the number of sides of the polygon.

18. If a polygon has n sides, then it has n-2 triangles.There are 18 triangles in a 20 sided polygon.

n

For a polygon with n sides, there would be n*(n-3)/2

A polygon with n sides can have n pairs of parallel sides (if n is even) or (n-1)/2 pairs if n is odd AND greater than 3. But it need not have any.

Infinitely many. For each integer n (greater than 2), there is a polygon with n sides or n vertices.

A pyramid is a generic term used to describe a polyhedron with a polygonal base and a number of triangles rising from that base to meet at an apex. A pyramid whose base is a polygon with n-sides (or vertices) has n+1 faces, n+1 vertices and 2n edges, where n >= 3.

A polygon with n sides had n*(n-3)/2 diagonals. So a 20 sided polygon would have 20*17/3 = 170

A 1260 degree polygon has nine sides. The formula for determining this is (n*180)+2, with n being equal to the degrees in the interior of the polygon.

n(n-3)/2

A polygon need not have any axes of symmetry. It can have at most n axes where n is the number of sides that the polygon has.

We solve the equation for n... since the sum of the interior angles is 180(n-2) where n is the number of sides of the polygon. So we have: 180(n-2)=1260 n-2=7 n=9 So 9 sides

An n polygon refers to a polygon with an unknown amount of sides.

In a polygon with n sides, we have n(n-3)/2 diagonals. In a convex polygon with n sides, you can draw n-3 diagonals from each vertex, but you are counting each one twice you so you need to divide by do. That is why we have n(n-3) divided by 2

A "n-gon" has n sides.n-gon is a generic term to mean a polygon with 'n' sides where the 'n' is any whole number greater than 3.Examples:a 3-gon is a polygon with 3 sides, normally called a triangle;a 6-gon is a polygon with 6 sides, normally called a hexagon;a n-gon is a polygon with n sides.

Sum of exterior angles = 360 degrees (whatever the number of sides). So, if the polygon has n sides, 360/n = 12 so that n = 360/12 = 30 sides.

The number of triangles that we can fit in a regular polygon with n sides is n - 2.

n: same as the number of sides.

If the polygon has n sides, the sum of its interior angles is 180*(n - 2) degrees. 180*(n - 2) = 7560 (n - 2) = 7560/180 = 42 n = 42 + 2 = 44 sides.

Exterior angles for n sides = 360/n = 17.14, n = 360/17.14 = 21 sides

A polygon with n sides has 1/2*n*(n - 3) diagonals. So, for a polygon, with n = 12, there are 54 diagonals.

A 3-sided polygon has 0 parallel sides. A 4-sided polygon can have 0, 2 or 4 parallel sides. A 5-sided polygon can have 0, 2, 3 or 4 parallel sides. In general, an n-sided polygon can have 0, 2, 3, ..., n-1, or n parallel sides where n>5. A polygon with n sides can have n pairs of parallel sides (if n is even) or (n-1)/2 pairs if n is odd AND greater than 3. But it need not have any.

If the polygon has n sides, then sum of interior angles = (n-2)*180 = 4320 so (n-2) = 4320/180 = 24 and so n = 24+2 = 26 sides.

A polygon with n sides has n*(n - 3)/2 diagonals. So n = 23 gives 23*20/10 = 230 diagonals