It has 16 sides
a convex polygon has 6 sides . What is the sum of the measure of its interior angles?
The sum of the interior angles of a triangle is 180 deg. For a convex polygon with n sides we can divide it to n-2 triangles. So the answer, if the polygon is convex, is (13-2)*180= 1980 deg * * * * * The polygon need not be convex. The formula for the sum of the interior angles is valid as long as the polygon is simple - that it, its sides do not cross each other inside the polygon.
The sum of the interior angles of any regular polygon of n sides is equal to 180(n - 2) degrees. Divide that by the number of sides.
The angles between adjacent sides of a polygon that are interior to the polygon. If the polygon is convex, the interior angles are always less than 180 degrees. If it is concave, at least one interior angle will be greater than 180 degrees.
If the polygon (convex or concave) has n sides, then the sum of its interior angles is 180*(n-2) degrees. The sum of its exterior angles is 360 degrees - irrespective of the number of sides.
A polygon is a closed plane figure bounded by straight sides. Since it is a closed surface, it has an interior (inside) and an exterior (outside). The interior angle of a polygon is the angle formed by two adjacent sides such that the angle is facing the interior of the polygon.
If it is a regular polygon and each interior angle is 176 degrees then it will have 90 sides.
The sum of the interior angles of a convex polygon with n sides is given by (n-2)x180o. So for a 40 sided polygon n=40; thus (40-2)x180o = 38x180o = 6840o.
If its a regular polygon then 180-interior angle and divide the answer into 360 which will give the number of sides of the polygon.
7560 degrees
Convex polygon. When the sides are extended, none of them pass through the polygon's interior.
48 sides A formula for finding the number of sides of a regular polygon given an interior angle: 360/(180-angle)=sides