Two of them.
Two of them.
1.6700 * 104 grams or 1.67*104 grams if the trailing 0s are not significant digits.
1.5*104 = 104(3)(.5) = 312/2 = 156. 3 digits.
It depends on how many significant digits you require; assuming 3 it's 1.82x10^41.82 x 104
192.1647
Two of them.
2.5000 has five significant digits and 104 has three significant digits. Therefore, the product should have three significant digits, and the answer is "260.". Note that the zero has to be made significant, so a decimal point is needed after the zero or you could put a vinculum (horizontal line) above the zero.
There are 5 significant digits in 78000. Which is the same as 7.8 x 104.
1.6700 * 104 grams or 1.67*104 grams if the trailing 0s are not significant digits.
1.5*104 = 104(3)(.5) = 312/2 = 156. 3 digits.
It depends on how many significant digits you require; assuming 3 it's 1.82x10^41.82 x 104
There are three rules that are used when rounding to a desired number of significant digits (figures): 1. All digits that are not zero, are significant 2. In a number that does not have a decimal point, all zeros between two non-zero digits are significant digits 3. In a number that has a decimal point, all zeros after the leftmost non-zero digit are significant Examples: 12345 rounded to 3 significant digits: 12300, or 1.23 x 104 12.345 rounded to 3 significant digits: 12.3, or 1.23 x 101 0.012345 rounded to 3 significant digits: 0.0123, or 1.23 x 10-2 0.012045 rounded to 3 significant digits: 0.0120, or 1.20 x 10-2 In the last example the zero after 2 is significant. That is the reason for keeping it in the result when rewriting it in powers of 10 notation.
192.1647
6 of them.
104 in 2 significant figures is 1.0e2
Assuming that the number in question is 7.99*104, the answer is 3.
104 = 10000 if digits can be repeated, 5040 if not. The above answers assume a code can start with a 0. If not, 9000 if digits can be repeated and 4536 if not.